get all username
Hello,
There is no API call to retrieve only usernames. Do not hesitate to go to this documentation page identity API.
(preferred) Implement a new Custom REST API extension
Bonita enables you to add a new REST API extension. It would provide in the body of a HTTP response the information needed as JSON: I.E. a list of userNames. Please have a look to this documentation page: REST API extensions
(not preferred) out-of-the-box Solution
The existing API/identity/user
REST resource, available with a GET HTTP request, enables you to retrieve a JSON, containing detailed information of the users. If a tomcat is running locally on the 8080 port, the URL below can be used to retrieve up to 10000 users:
http://localhost:8080/bonita/API/identity/user?p=0&c=10000
UID FORM edition example
A UID form's variable can be used to
- either sends a HTTP request and stores the JSON response: External API,
- or stores the result of the execution of javascript lines of code: javascript expression.
This example shows how to store the usernames of many users in a UID Form's variable named allUserNames
.
Click on the Create a new variable button in order to create a variable with name allUsers, type External API, and value ../API/identity/user?p=0&c=10000
Create a second variable with name allUserNames, type Javascript expression, value
var usernames = []; for (var i=0; i<$data.allUsers.length; i++) { usernames.push($data.allUsers[i].userName); } return usernames;
Regards,
Jerome
Comments
Hi Jerome,
thanks for reply actually from this we will get all the users from the organizations but I want only archieved usernames only.
For example i have three tasks user1 for step1 , user2 for step2 , user3 for step3 now I want user1 in step2 and also user1 and user2 in step3 . Thanks in advance.
var getAuditDetailJSON = [];
getAuditDetailJSON = $data.auditDetails;
var auditTrail = [];
for(var i= 0;i<getAuditDetailJSON.length;i++){
var userId = getAuditDetailJSON[i].executedBy;
var taskName = getAuditDetailJSON[i].displayName;
var dateTime = getAuditDetailJSON[i].archivedDate;
}
return auditTrail;
please look into the above code which i created in javascxcript variable in ui designer i am displaying userId,taskName,date and userName, for username i am using var user_name = ..API/identity/user/{{userId}} but i am not geetting username from this it is showing syntax error. Please help me is ther any other way to achieve this. Thanks in advance.
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@ramireddy.pingala: The answer had been edited to clarify, I hope. To send HTTP requests, you need to use either javascript function either UID variables.
@ramireddy.pingala: The answer had been edited to clarify, I hope. To send HTTP requests, you need to use either javascript function (XMLHttpRequest) either a UID variable with type External API.
Hi,
Still I didn't get any solution for this isssue, I solved this issue by saving the details into the database and retriveing through webService. I solved this problem like this.
Thank you