How to upload a file alfresco with Bonita some reference code

Q&A
1

please a page with a manual upload files with alfresco through BonitaSoft not want to help me official since there is not much information

Thank You So Much

2

Ok I understand it might help with a recommendation on this issue .

I need to connect these technologies and good conduct a suitable solution for customers

That Alfresco is advisable to work with the BonitaSoft in version 6.3.6

3

first things first, what version of Alfresco?

As you will notice there are only connectors for 3.2 and 4.2. If you are using 5+ then you will have to write code, you could try to use CMIS connector but it might be easier overall to use REST which is supported by Alfresco

Sorry I have no code for that. See Links below.

There is no official word on this and I do not speak for BonitaSoft but I suspect the interface with Alfresco is being depreciated from both sides as Alfresco also has a competing BPM system

regards
Seán

http://stackoverflow.com/questions/14689480/access-to-alfresco-rest-apis
http://docs.alfresco.com/5.0/references/RESTful-intro.html

4

Ok I understand it might help with a recommendation on this issue .

I need to connect these technologies and good conduct a suitable solution for customers

That Alfresco is advisable to work with the BonitaSoft in version 6.3.6

5

what version Alfresco are you using?

6

I’m using version 3.4 alfresco

This is the code I use

import org.bonitasoft.engine.api.APIAccessor;
import org.bonitasoft.engine.bpm.document.impl.DocumentImpl;

DocumentImpl d=apiAccessor.getProcessAPI().getDocumentAtProcessInstantiation(processInstanceId, “prueba”);
String tipo=apiAccessor.getProcessAPI().getDocumentAtProcessInstantiation(processInstanceId, “prueba”).getContentMimeType();
String nombre=apiAccessor.getProcessAPI().getDocumentAtProcessInstantiation(processInstanceId, “prueba”).getName();
String algo=apiAccessor.getProcessAPI().getDocumentAtProcessInstantiation(processInstanceId, “prueba”).getContentFileName();
File doc=new File(“c:/archivos”+algo);
def byte myByte = apiAccessor.getProcessAPI().getDocumentContent(d.getContentStorageId());
doc.delete()
doc.withOutputStream { s →
s << myByte
}

return doc.absolutePath;